Question

write a Pythagorean triplet whose one
number is 8​

Answer 1

Answer:

=64

⇒ 100−64=36

⇒

36

=6

⇒

100

=10

Let

Hypotenuse =10 [ Since its greater than 6 and 8 ]

Base =8 and

Perpendicular =6

(Hypotenuse)

2

=(Perpendicular)

2

+(Base)

2

[ Pythagoras theorem ]

⇒ (10)

2

=(6)

2

+(8)

2

⇒ 100=36+64

⇒ 100=100

∴ Pythagorean triplet are 6,8,10

Step-by-step explanation:

hope it might help you

Answer 2

Given

A Pythagorean triplet whose smallest number is 8

Answer

We have to find the Pythagorean triplet

Solution

Pythagoras triplets are of the form 2m, m² -1 and m² + 1.

It is given that the smallest number is 8.

So, 2m = 8.

m = 4

Now,

second number = m² -1 = 4² – 1 = 15

third number = m² + 1 = 4² + 1 = 17.

Hence, the triplet is 8, 15 and 17.

This can be verified as

17² = 8² + 15²

289 = 64 + 225

289 = 289.

Hence, proved...