Question

write a Pythagorean triplet whose one number is 80​

Answer 1

Answer:

THE PYTHAGOREAN TRIPLET WHOSE ONE MEMBER IF 80NTHEN OTHERS Are 18&82 so overall Pythagorean triplet is

18,80,82

HOPE IT HELPS U

Answer 2

Answer:

(80 , 1599 , 1601) or (18 , 80 , 82)

Note:

★ Three numbers a , b , c ( a > b , c ) are said to be a Pythagorean triplet if a² = b² + c² .

★ The form of a phythagorean triplet is given by ; ( 2m , m² - 1 , m² + 1 ).

Solution:

We need to form Pythagorean triplet whom one of the number is 80.

Here ,

Two Pythagorean triplets are possible with the number 80.

Case(1) : If 2m = 80

=> 2m = 8

=> m = 80/2

=> m = 40

Thus,

=> m² - 1 = 40² - 1

=> m² - 1 = 1600 - 1

=> m² - 1 = 1599

Also,

=> m² + 1 = 40² + 1

=> m² + 1 = 1600 + 1

=> m² + 1 = 1601

Hence,

Required Pythagorean triplet is :

80 , 1599 , 1601 .

°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°

Case(2) : If m² - 1 = 80

=> m² - 1 = 80

=> m² = 80 + 1

=> m² = 81

=> m = √81

=> m = 9

Thus,

=> 2m = 2×9

=> 2m = 18

Also,

=> m² + 1 = 9² + 1

=> m² + 1 = 81 + 1

=> m² + 1 = 82

Hence,

The required Pythagorean triplet is ;

18 , 80 , 82 .