Question

write a Pythagorean triplet whose one number is a 10 B 18​

Answer 1

so 2m,m^2+1,m^2-1

2m=10

m=5

m^2-1=24

m^2+1=26

$....$

2m=18

m=9

m^2-1=80

m^2+1=82

$....$

Answer 2

2m = 10

m = 5

5x5 =25-1 25+1

24 and 25

2m = 18

m = 9x9 =81-1 81+1

80 and 82