Question

Write a pythagorean triplet whose one of the members is 20 [For m>1(2m,m2-1,m2+1)is a Pythagorean triplet]​

Answer 1

Step-by-step explanation:

For any natural numbers m>1,2m, m

2

−1, m

2

+1 forms a Pythagorean triplet.

If we take m

2

+1=20, then m

2

=19

The value of m will not be an integer.

If we take m

2

−1=20, then m

2

=21

Again the value of m will not be an integer.

Let 2m=20

=>m=10

∴2m=2⋅10=20

m

2

−1 = 10

2

−1=99

and

m

2

+1 = 10

2

+1=101

Answer 2

Step-by-step explanation:

The Pythagorean Triplet is of the form

(2m,m²-1,m²+1)

One of the members is 20

As for any positive integer m²-1 and m²+1 can not be equal to 20,

so 2m=20.

=> m=20/2=10

so m²-1=10²-1=100-1=99

and m²+1=10²+1=100+1=101

Thus the Pythagorean Triplet is ( 20,99,101)

hope it will help you.