Write a Pythagorean triplet whose smallest member is:
1) 6
2) 14
3) 16
4) 20
Answers
Step-by-step explanation:
1) .
As we know 2m, m² + 1 and m²- 1 form a Pythagorean triplet for any number, m > 1.
Let us assume 2m = 6
Therefore, m = 3
And, m² + 1 = 3² + 1= 9 + 1 = 10
And, m²- 1 = 3²- 1 = 9 - 1 = 8
Test: 6² + 8² = 36 + 64 = 100 = 102
Hence, the triplet is 6, 8, and 10 Answer
2).
Formula=(2m)²,(m²-1)².(m²+1)²
according to ques
smallest number =14
means 2m =14
m=14/2=7
m²-1= 7²-1= 49-1= 48
m²+1=7²+1= 49+1=50
hence the required triplet is 14, 48 and 50
3).
The formula is (2m)²,(m² - 1)²,(m² + 1)²
smallest no. = 2m = 16
2m = 16
m = 8
m²-1 = 64 -1 = 63
m² + 1 = 64 + 1 = 65
Thus, the Pythagorean triplet is 8, 63 ,65
4).
Pythagorean triplet = 2m , m² + 1 , m² - 1
2m = 20. So
m = 20/2=10
m²+1= 10²+ 1 = 101
m²-1 = 10² - 1 = 99
So pythagorean triplets are 20 , 99 and 101
Hope this will help you :)