Question

write a pythagorean triplet whose smallest member is 14​

Answer 1

Step-by-step explanation:

Given 14 is the smallest number in Pythagorean triplet

But we have for every number m>1, we have (2m,m

2

−1,m

2

+1) as a Pythagorean triplet

2m=14

m=14/2=7

Then m

2

=49

m

2

−1=49−1=48

m

2

+1=49+1=50

Therefore the Pythagorean triple is =(2m,m

2

−1,m

2

+1)=(14,48,50)

Answer 2

Answer:

2m= 14

m=7

First number= 7^2+1= 49+1=50

Second Number= 7^2-1=49-1=48