Question

- Write a Pythagorean triplet whose smallest member is
14​

Answer 1

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The triplet is = 14 , 48 , 50 .

Answer 2

Answer:

Hi

Step-by-step explanation:

Given 14 is the smallest number in Pythagorean triplet But we have for every number m>1,

we have (2m, m2-1, m2+1) as a Pythagorean triplet

Using the above condition we can write as 2m = 14 m= 14/2=7 Then m2 =49 m2 – 1 = 49 – 1 = 4

8 m2 + 1 = 49 + 1 =50

Therefore the Pythagorean triplet is = (2m, m2-1, m2+1) = (14, 48, 50)

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