Question

write a Pythagorean triplet whose smallest member is 8​

Answer 1

Answer: 8, 15, 17

Step-by-step explanation:

Pythagoras triplets are of the form.

2m, m² -1 and m² + 1.

It is given that smallest number is 8.

So, 2m = 8.

m = 4.

Now, second number = m² -1 = 4² - 1 = 15.

and, third number = m² + 1 = 4² + 1 = 17.

Hence, the triplet is 8, 15 and 17.

Verification :-

17² = 8² + 15²

289 = 64 + 225

289 = 289.

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Answer 2

Here's your answer.

Hope it helps.