Math, asked by radhabhatt001, 1 month ago

Write a Pythagorean triplet whose smallest member is 8.​

Answers

Answered by rakeshkarri79
0

Answer:

Example 2 Write a Pythagorean triplet whose smallest member is 8. We know 2m, ^2−1 and ^2+1 form a Pythagorean triplet. Given, Smallest member of the triplet = 8. Let 2m = 8 2m = 8 m = 8/2 m = 4 Let ^−" = 8" ^2 = 8 + 1 ^2 = 9 ∴ m = 3 Let ^+ = 8 ^2 = 8 − 1 ^2 = 7 Since, 7 is not a square number, ∴ ^2+1 ≠ 8 It is not possible.

Step-by-step explanation:

ok ヽ(✿゚▽゚)ノ

Answered by shreyasumit1234
0

Answer:

8,16,24

Step-by-step explanation:

8,16,24

HOPE IT WILL HELP YOU

MARK BRANLIEST

Similar questions