write a Pythagorean triplet whose smallest member is 8 and verify your answer....plz answer
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Answered by
11
Given in the question
Smallest member is 8
2m=8
m=8/2
= 4
m^2+1=8^2+1
m^2-1=8^2-1
So the members are 8,17,15
The smallest member is 8 as given in the question
PLS MARK BRAINLIEST IF IT HELPS YOU
Smallest member is 8
2m=8
m=8/2
= 4
m^2+1=8^2+1
m^2-1=8^2-1
So the members are 8,17,15
The smallest member is 8 as given in the question
PLS MARK BRAINLIEST IF IT HELPS YOU
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PLS MARK BRAINLIEST IF IT HELPS YOU
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Answered by
0
Answer:
15, 17
Step-by-step explanation:
8^2+15^2=17^2
64+225=289
289=289
Hence Verified
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