write a Pythagorean triplet whose smallest member is 8 and verify your answer
Answers
Answered by
1
Answer:
8,17,18
Is the required triplet
Step-by-step explanation:
Answered by
5
Answer:
Pythagoras triplets are of the form.
2m, m² -1 and m² + 1.
It is given that smallest number is 8.
So, 2m = 8.
m = 4.
Now, second number = m² -1 = 4² - 1 = 15.
and, third number = m² + 1 = 4² + 1 = 17.
Hence, the triplet is 8, 15 and 17.
Verification :-
17² = 8² + 15²
289 = 64 + 225
289 = 289.
Hence, proved.
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