Math, asked by Shubham09102004, 1 year ago

write a Pythagorean triplet whose smallest no. is 6

Answers

Answered by FZD
12
Pythagoras triplet
=√x²+ √y²= √x²+y²
Therefore triplet is 6 8 10
Where 6²+8²= 36+64=100=10²
Hence triplet is 6 8 and 10
Answered by Anonymous
13
Hi friend,

Here is your answer,

The Pythagorean triplet whose smallest no. is 6 is 6,8,10
Proof:-
6
²+8²=10²
LHS:
    36 + 64
= 100
= RHS


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