Math, asked by suzzi57yadav, 11 months ago

write a pythagorean triplet whose smallest no is 6

Answers

Answered by Aquib7089
2
6 8 and 10
6'2 + 8'2 = 10 '2
36 + 64 = 100
100 = 100

suzzi57yadav: thanks a lot dear
Answered by santhoshkumarm75
2

Answer:

6, 8 and 10

Step-by-step explanation:

2m,m^2+1 , m^2-1 is a Pythagorean triplet

2m=6

m=6/2

m=3

m^2-1=3^2-1

=9-1

=8

m^2+1=3^2+1

= 9+1

=10

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