write a pythagorean triplet whose smallest no is 6
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6 8 and 10
6'2 + 8'2 = 10 '2
36 + 64 = 100
100 = 100
6'2 + 8'2 = 10 '2
36 + 64 = 100
100 = 100
suzzi57yadav:
thanks a lot dear
Answered by
2
Answer:
6, 8 and 10
Step-by-step explanation:
2m,m^2+1 , m^2-1 is a Pythagorean triplet
2m=6
m=6/2
m=3
m^2-1=3^2-1
=9-1
=8
m^2+1=3^2+1
= 9+1
=10
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