Question

write a Pythagorean triplet whose smallest number is 14​

Answer 1

Answer:

Formula=(2m)²,(m²-1)².(m²+1)²

given in the question

smallest number =14

means 2m =14

 m=14/2=7

m²-1= 7²-1= 49-1= 48

m²+1=7²+1= 49+1=50

hence the required triplet is 14, 48 and 50

Hope it will be helpful...

Answer 2

Formula=(2m)²,(m²-1)².(m²+1)²

Now, According to question,

Smallest number = 14

i.e. 2m =14

→ m = 14/2 = 7

So, m² - 1 = 7² - 1 = 49 - 1 = 48

And, m² + 1 = 7² + 1 = 49 + 1 = 50

Hence, the required triplets are

14, 48 and 50