Math, asked by radha1114, 1 year ago

write a Pythagorean triplet whose smallest number is 6​

Answers

Answered by beautyandbrains
1

Answer: 6, 8 and 10.

Step-by-step explanation:

6^2 = 36

8^2=64

10^2 = 100

If Pythagorean triplet then 6^2 + 8^2 = 10^2

LHS

6^2+8^2

= 36+64

=100

RHS

10^2

=100

Hence LHS = RHS

Thus 6,8 and 10 are Pythagorean triplets in which 6 is the smallest number.

Hope this helped

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Answered by BrainliestSuperGIRL
0

Answer:

6,8,10

Step-by-step explanation:

Given 6 is the smallest number in Pythagorean triplet

But we have for every number m>1, we have (2m,m  

2

−1,m  

2

+1) as a Pythagorean triplet

2m=6

m=6/2=3

Then m  

2

=9

m  

2

−1=9−1=8

m  

2

+1=9+1=10

Therefore the Pythagorean triple is =(2m,m  

2

−1,m  

2

+1)=(6,8,10)

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