write a Pythagorean triplet whose smallest number is 6
Answers
Answered by
1
Answer: 6, 8 and 10.
Step-by-step explanation:
6^2 = 36
8^2=64
10^2 = 100
If Pythagorean triplet then 6^2 + 8^2 = 10^2
LHS
6^2+8^2
= 36+64
=100
RHS
10^2
=100
Hence LHS = RHS
Thus 6,8 and 10 are Pythagorean triplets in which 6 is the smallest number.
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Answered by
0
Answer:
6,8,10
Step-by-step explanation:
Given 6 is the smallest number in Pythagorean triplet
But we have for every number m>1, we have (2m,m
2
−1,m
2
+1) as a Pythagorean triplet
2m=6
m=6/2=3
Then m
2
=9
m
2
−1=9−1=8
m
2
+1=9+1=10
Therefore the Pythagorean triple is =(2m,m
2
−1,m
2
+1)=(6,8,10)
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