Question

write a pythagorean triplet whose smallest number is 6​

Answer 1

Answer:

your answer is here....

Step-by-step explanation:

Formula of Pythagorean triplet= 2n, (n^2+1), (n^2 -1)

= n/2= 6/2 =3

= (n^2 +1) = (3^2 +1) = 9+1 =10

=( n^2 -1) = (3^2 -1) =9 -1 =8

so, the answer is 6, 10 and 8

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Answer 2

Step-by-step explanation:

For any natural number n>1

2n,n2−1,n2+1 forms a pythagoras triplet.

Here,the smallest number is 2n

Given,

2n=6

=>n=3

∴ Other are

n2−1

=3^2−1=9−1=8

And,

n2+1

=3^2+1 =9+1=10

6,8,10 is the Pythagorean triplet