Question

write a Pythagorean triplet whose smallest number is 8

Answer 1

Here m will be 4 ( 2m = 8, m= 4)
After that...2m + 1 = 2×4+1= 9...
And 2m-1= 7...

So, the triplet is 7,8 and 9...

Hope it help$ ...

Answer 2

We can get Pythagorean triples by using general from 2 m, m²,m² + 1.

Let us first take m² -1=8

So, m²=8 + 1 =9

Which gives m=3

Therefore, 2m=6 and m² +1 =10

The triplet is thus 6,8,10.But 8 is not the smallest number of this.

So, let us try 2m= 8

Then m=4

We get,

$m {}^{2} - 1 = 16 - 1 = 15$

and

$m {}^{2} + 1 = 16 + 1 = 17$

The triplet is 8,15,17 with 8 as the smallest number.