Question

Write a pythagorean triplet whose smallest number is 8 and verify your answer

Answer 1

Heya !!!

This is Your Answer...

Pythagoras triplets are of the form.
2m, m² -1 and m² + 1.

It is given that smallest number is 8.
So, 2m = 8.
m = 4.

Now, second number = m² -1 = 4² - 1 = 15.
and, third number = m² + 1 = 4² + 1 = 17.

Hence, the triplet is 8, 15 and 17.

Verification :-
17² = 8² + 15²
289 = 64 + 225
289 = 289.

Hence, proved.

Hope It Helps

Source: https://brainly.in/question/2661168

Answer 2

8,15,17
17²=8²+15²
289=64+225...