Question

write a Pythagorean triplet whose smallest number is 8 and verify your answer

Answer 1

smallest no. is 8 so let
2n  = 8
n = 4
$n^{2}$ +  1 = 17
$n^{2}$  -  1 = 15
so the triplet is 8, 17 and 15
we can prove it by
8 squared + 15 squared = 17 squared

Answer 2

For any natural number m>1, 2m,m2-1,m2+1 forms pytharorean triplet.
Take m=4
So required triplet = 8,15,17

Hope it helps
please mark as brainliest...