Question

write a pythagorean triplet whose smallest number is 9​

Answer 1

Answer:

9,40 , 41

Step-by-step explanation:

formila for finding Pythagorean triplet when smallest number is odd

let the smallest number pe b then the triplets are

$p \: \: \: \: \: \: \frac{ {p}^{2} - 1 }{2} \: \: \: \frac{{p}^{2} + 1}{2}$

so here p = 9 putting this we get our triplet as

9 , 40 , 41

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