Question

Write a Pythagorean triplets whose one member is 14,16

Answer 1

Answer:fhkxk

Step-by-step explanation:

Answer 2

Answer:

14

Let m²-1=14=m²=1+14=15

The value of m will not be an integer

now take 2m=14=>m=7 which is an integers

The member of triplets are 2m=2×7=14

m²-1=(7)²-1=49-1=48 and

m² +1=(7)²+1=49+1=50

i.e,(14,48,50)

Step-by-step explanation:

16

Let 2m=16m=8

The required triplets are 2m=2×8=16

m²-1=(8)²-1=64-1=63

m²+1=(8)²=1=64+1=65

i.e .(16,63,65)