Question

write a Pythagorean triplets whose one member is 14​

Answer 1

Let us assume 2 m=14 therefore m=7

Now m

2

+1=7

2

+1=49+1=50

And m

2

−1=7

2

−1=49−1=48

Test : 14

2

+48

2

=196+1304=2500=50

2

Hence the triplet is 14,48 and 50 Answer

Answer 2

Answer:

let

2n=14

n=7

now,

n^2+1=7^2+1

=50

the required triplet is 14,48,50