Write a pythgorean triplet whose one member is 14
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Answer:
Hence the square of the largest number is equal to the sum of the squares of remaining two numbers. Therefore ( 14, 48, 50) is a Pythagorean triplet.
Step-by-step explanation:
Let,
2n = 14
n = 7
now,
n²-1 =7²-1 =48
now,
n²+1 =7²+1 =50
Therefore ( 14, 48, 50) is a Pythagorean triplet.
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