Question

write a pythogerous tripless by using general form whose smallest number is 8​

Answer 1

Pythagoras triplets are of the form 2m, m² -1 and m² + 1.

It is given that smallest number is 8.

So, 2m = 8.

m = 4

Now, second number = m² -1 = 4² – 1 = 15 and, third number

= m² + 1 = 4² + 1 = 17.

Hence, the triplet is 8, 15 and 17.

This can be verified

17² = 8² + 15²

289 = 64 + 225

289 = 289.Hence, proved.