Question

Write a pythogoream tiplet whose one numner is 16
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Answer 1

Answer:

Three natural numbers m,n and p are said to form a Pythagorean Triplet (m,n,p),

if m²+n² = p².

For every natural number m>1,

we have (2m,m²-1,m²+1) as a Pythagorean Triplet.

Here,

m = 16,

2m= 2×16 = 32

m²-1 = 16² - 1 = 256 -1 = 255

m²+1 = 16²+1 = 256 +1 = 257

Therefore,

Required Pythagorean Triplet:

(32,255,257)

Step-by-step explanation:

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Answer 2

Answer:

2m=16

m=16/2=8

m=8

m²-1=8²-1

=64-1

=63

m²+1=8²+1

64+1=65