Question

Write a Python function subsequence(l1,l2) that takes two sorted lists as arguments and returns True if the the first list is a subsequence of the second list, and returns False otherwise.

A subsequence of a list is obtained by dropping some values. Thus, [2,3,4] and [2,2,5] are subsequences of [2,2,3,4,5], but [2,4,4] and [2,4,3] are not.

Answer 1

Answer:

A function all() compares the items in the lists and return True if every item is truthy, else return False.

Explanation:

Python Code:

l1=[2,3,4]                      #let elements in L1

l2=[2,2,5]                     #let elements in l2

def subsequence(l1,l2):

   if(all(x in l1 for x in l2)):

       print("True")

   else:

       print("False")

subsequence(l1,l2)        #function calling

Answer 2

Python code to compare the list values:

Output:

False

Explanation:

code:

def subsequence(l1,l2):#defining the method subsequence that accepts two lists

  if(all(i in l1 for i in l2)):#defining if block that checks list values

      print("True") #use print method to return true value

  else:#defining else block

      print("False")#use print method to return false value

l1=[2,3,4] #defining list1 and assign value

l2=[2,2,5] #defining list2 and assign value

subsequence(l1,l2) #call the function subsequence

Code description:

• In the above-given code, a method "subsequence" is defined that uses two lists in its parameters, in the next step, if block is declared that uses the "all" method.
• In this method, it checks list element values if it matches it prints "true" as a message or goes to else block, in this it will print "False" as the message.
• Outside the method, the two lists "l1 and l2" is declared, that stores the value and pass to the method and call it.

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