Write a python function to check whether three given numbers can form the sides of a triangle.
Answers
Clearing the Question:
You need to specify what those three numbers are?
Are they coordinated on a cartesian plane?
Or are they measure of sides of the triangle ?
Or they are the interior angles of the triangle?
Since you haven't mentioned I guess I'll have to answer all three scenarios.
Language:
Python
Coordinated on a cartesian plane:
Program:
print("Enter the coordinates in x1,y1,x2,y2,x3,y3 order:")
c=[ int(input(f"value {i+1}: ")) for i in range(0,6)]
det=c[0]*(c[3]-c[5])+c[2]*(c[5]-c[1])+ c[4]*(c[1]-c[3])
if det==0:
print(f"Traingle not possible through ({c[0]},{c[1]}),({c[2]},{c[3]}),({c[4]},{c[5]}).")
else:
print(f"Traingle possible through ({c[0]},{c[1]}),({c[2]},{c[3]}),({c[4]},{c[5]}). ")
Logic:
- Get coordinates
- Check using 0.5* [x1(y2−y3)+x2(y3−y1)+x3(y1−y2]) if area is 0.
- If yes triangle not possible if no then it is.
Sides of the triangle :
Program:
a=int(input("Enter side1:" ))
b=int(input("Enter side2:" ))
c=int(input("Enter side3:" ))
if (a+b<=c) or (b+c<=a) or (c+a <=b):
print(f"Traingle of side lengths {a},{b},{c} not possible. ")
else:
print(f"Traingle of side lengths {a},{b},{c} possible. ")
Logic:
- Enter the triangle sides
- check if sum of any 2 sides is equal to or smaller than third
- If yes then triangle can't exist
Interior angles of the triangle:
Program:
a=int(input("Enter angle1 (in degrees):" ))
b=int(input("Enter angle2 (in degrees):" ))
c=int(input("Enter angle3 (in degrees):" ))
if a+b+c!=180:
print(f"Traingle of interior angle {a},{b},{c} not possible. ")
else:
print(f"Traingle of interior angle {a},{b},{c} possible. ")
Logic:
- Enter interior angles
- check if sum is 180 degrees.
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