Question

Write a Python program that reads marks in six
subjects and assign grades of marks:

% Marks. Grades

> 90. O
80-90. E
70-80. A
60-70 . B
50-60. C
40-50. D
<40. F


​

Answer 1

Answer:

sub1=int(input("Enter marks of the first subject: "))

sub2=int(input("Enter marks of the second subject: "))

sub3=int(input("Enter marks of the third subject: "))

sub4=int(input("Enter marks of the fourth subject: "))

sub5=int(input("Enter marks of the fifth subject: "))

avg=(sub1+sub2+sub3+sub4+sub4)/5

if(avg>=90):

print("Grade: A")

elif(avg>=80&avg<90):

print("Grade: B")

elif(avg>=70&avg<80):

print("Grade: C")

elif(avg>=60&avg<70):

print("Grade: D")

else:

print("Grade: F")

Explanation:

1. User must enter 5 different values and store it in separate variables.

2. Then sum up all the five marks and divide by 5 to find the average of the marks.

3. If the average is greater than 90, “Grade: A” is printed.

4. If the average is in between 80 and 90, “Grade: B” is printed.

5. If the average is in between 70 and 80, “Grade: C” is printed.

6. If the average is in between 60 and 70, “Grade: D” is printed.

7. If the average is anything below 60, “Grade: F” is printed.

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Answer 2

Explanation:

sum=0

for i in range(6):

mrx=float(input("marks : "))

sum=sum+mrx

per=sum/6

print("Percentage : ",per)

if(per>90):

print("Grade : O")

elif(80<per<=90):

print("Grade : E")

elif(70<per<=80):

print("Grade : A")

elif(60<per<=70):

print("Grade : B")

elif(50<per<=60):

print("Grade : C")

elif(40<=per<=50):

print("Grade : D")

elif(per<40):

print("Grade : F")