Write a python program to accept any integer number and display its multiple of 3 and 5
or not.
Answers
Answered by
2
Explanation:
There are floor(999/3) multiples of 3, floor(999/5) multiples of 5, and floor(999/15) multiples of 15 under 1000. = 3 * (333 * 334 / 2) because the sum of the integers from 1 to k is k*(k+1)/2. Use the same logic for the sum of multiples of 5 and 15. This gives a constant time solution
Answered by
0
Answer: x=int(input("Enter a number : "))
for i in range(1,6):
print(i*x)
Explanation: Please mark me as brilliant
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