Question

Write a python program to calculate parking charges of a vehicle. Enter the type of vehicle as a character (like c for car, b for bus, etc.) and number of hours, then calculate charges as given below: Truck/bus - 20 per hour Car - 10 per hour Scooter/ Cycle/ Motor cycle-5 per hour ​

Answer 1

$\huge{\green{\underbrace{\overbrace{\blue{\mathfrak{answer::}}}}}}$

$\huge{\sf{\underline{Python::}}}$

vehicle = int(input())

hours = int(input())

if vehicle == "t" or vehicle == "b":

    print(hours * 20)

elif vehicle == "c" :

    print(hours * 10)

elif vehicle == "s" or vehicle == "m":

    print(hours * 5)

else:

    print("Wrong choice")

$\bold{\sf{\underline{Logic::}}}$

• We took vehicle name as input and hours too.
• Then we built a conditional framework using if-elif-else statements.
• There is a statement in else block that prints wrong choice if none of the choice is met.

I hope that my answer helps you...

Answer 2

Answer:

vehicle=input("Enter s for 2-wheeler; c for 4-wheeler and b for bus/truck")

hours=int(input("Enter the number of hours in which the vehicle was parked"))

if vehicle=="s":

if hours<=3:

print("Total price for 2-wheeler is", (hours*20))

else:

total=hours-3

price=60+total*30

print("Total price for 2-wheeler is", price)

elif vehicle=="c":

if hours<=3:

price=hours*40

print("Total price for 4-wheeler is", price)

else:

total=hours-3

price=120+total*50

print("Total price for 4-wheeler is", price)

elif vehicle=="b":

if hours<=3:

price=hours*70

print("Total price for bus/truck is", price)

else:

total=hours-3

price=210+total*80

print("Total price for bus/truck is", price)

else:

print("Wrong choice")

Explanation:

the price for parking upto 3 hours is different from the rest