Question

Write a Python program to change the position of every n-th value with the (n+1)th in a list.  Sample list: [0,1,2,3,4,5] Expected Output: [1, 0, 3, 2, 5, 4]
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Answer 1

def change_pos(my_list):

      for i in range(0,len(my_list),2):

           my_list[i],my_list[i+1]=my_list[i+1],my_list[i]

           return my_list

my_list=[0,1,2,3,4,5]

print(change_pos(my_list))

Answer 2

Answer:

def change_pos(lst):

   for i in range(0, len(lst)-1, 2):

       lst[i], lst[i+1] = lst[i+1], lst[i]

   return lst

# Sample list

my_list = [0,1,2,3,4,5]

# Change the position of every n-th value with the (n+1)th

result = change_pos(my_list)

# Print the result

print(result)

Explanation:

This program defines a function called "change_pos()" that takes a list as an input. The function uses a for loop to iterate through the list, starting at the 0th index and incrementing by 2 each time. Inside the for loop, the function uses tuple unpacking to swap the n-th value with the (n+1)th value. Then it returns the modified list.

In the main function, the program creates a sample list and calls the change_pos() function passing the sample list as an argument. It then prints the modified list as a result.

The expected output of this program is [1, 0, 3, 2, 5, 4].

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