Question

Write a Python Program to find the Julian date for the given date without using inbuilt functions.

Answer 1

Answer:

# Python3 program two find number of

# days between two given dates

# A date has day 'd', month

# 'm' and year 'y'

class Date:

def __init__(self, d, m, y):

self.d = d

self.m = m

self.y = y

# To store number of days in

# all months from January to Dec.

monthDays = [31, 28, 31, 30, 31, 30,

31, 31, 30, 31, 30, 31 ]

# This function counts number of

# leap years before the given date

def countLeapYears(d):

years = d.y

# Check if the current year needs

# to be considered for the count

# of leap years or not

if (d.m <= 2) :

years -= 1

# An year is a leap year if it is a

# multiple of 4, multiple of 400 and

# not a multiple of 100.

return int(years / 4 - years / 100 +

years / 400 )

# This function returns number of

# days between two given dates

def getDifference(dt1, dt2) :

# COUNT TOTAL NUMBER OF DAYS

# BEFORE FIRST DATE 'dt1'

# initialize count using years and day

n1 = dt1.y * 365 + dt1.d

# Add days for months in given date

for i in range(0, dt1.m - 1) :

n1 += monthDays[i]

# Since every leap year is of 366 days,

# Add a day for every leap year

n1 += countLeapYears(dt1)

# SIMILARLY, COUNT TOTAL NUMBER

# OF DAYS BEFORE 'dt2'

n2 = dt2.y * 365 + dt2.d

for i in range(0, dt2.m - 1) :

n2 += monthDays[i]

n2 += countLeapYears(dt2)

# return difference between

# two counts

return (n2 - n1)

# Driver Code

dt1 = Date(1, 2, 2000 )

dt2 = Date(1, 2, 2004 )

print("Difference between two dates is",

getDifference(dt1, dt2))