Question

Write a Python program to find the smallest of 3 numbers using if..elif.

Answer 1

Read 3 input numbers using input() or raw_input().

Use two functions largest() and smallest() with 3 parameters as 3 numbers

largest(num1, num2, num3)

check if num1 is larger than num1 and num2, if true num1 is largest, else

check if num2 is larger than num1 and num3, if true num2 is largest,

if both the above fails, num3 is largest

Print the largest number

smallest(num1, num2, num3)

check if num1 is smaller than num1 and num2, if true num1 is smallest, else

check if num2 is smaller than num1 and num3, if true num2 is smallest,

if both the above fails, num3 is smaller

Print the smallest number

Program :

number1 = int(input('Enter First number : '))

number2 = int(input('Enter Second number : '))

number3 = int(input('Enter Third number : '))def largest(num1, num2, num3):

if (num1 > num2) and (num1 > num3):

largest_num = num1

elif (num2 > num1) and (num2 > num3):

largest_num = num2

else:

largest_num = num3

print("The largest of the 3 numbers is : ", largest_num)def smallest(num1, num2, num3):

if (num1 < num2) and (num1 < num3):

smallest_num = num1

elif (num2 < num1) and (num2 < num3):

smallest_num = num2

else:

smallest_num = num3

print("The smallest of the 3 numbers is : ", smallest_num)largest(number1, number2, number3)

smallest(number1, number2, number3)

Answer 2

Answer:

hello

Get three inputs num1, num2 and num3 from user using input() methods. Check whether num1 is smaller than num2 and num3 using if statement, if it is true print num1 is smallest using print() method. Else, num2 or num3 is smallest. So check whether num2 is smaller than num3 using elseif statement.