Write a python program to generate and display the next date of a given date.
Assume that
Date is provided as day, month and year as shown in below table.
The input provided is always valid. Output should be day-month-year.
Hint: print(day,"-",month,"-",year) will display day-month-year
Sample Input Expected Output
Day 1 2-9-2015
Month 9
Year 2015
Also identify the test data and use it to test the program.
Answers
Answer:
year = int(input("Input a year: "))
if (year % 400 == 0):
leap_year = True
elif (year % 100 == 0):
leap_year = False
elif (year % 4 == 0):
leap_year = True
else:
leap_year = False
month = int(input("Input a month [1-12]: "))
if month in (1, 3, 5, 7, 8, 10, 12):
month_length = 31
elif month == 2:
if leap_year:
month_length = 29
else:
month_length = 28
else:
month_length = 30
day = int(input("Input a day [1-31]: "))
if day < month_length:
day += 1
else:
day = 1
if month == 12:
month = 1
year += 1
else:
month += 1
print("The next date is [dd-mm-yyyy] %d-%d-%d." % (day, month, year))
Python program to generate and display the next date of a given date.
Language using : Python Programming
Program :
day=int(input("Enter the day :"))
month=int(input("Enter the month :"))
year=int(input("Enter the year :"))
if year%400==0 or (year%4==0 and year%100!=0):
#leap year
if month==2:
no_of_days=29
elif month in [4,6,9,11]:
no_of_days=30
else:
no_of_days=31
else:
#not a leap year
if month==2:
no_of_days=28
elif month in [4,6,9,11]:
no_of_days=30
else:
no_of_days=31
if day<no_of_days:
print(day+1,"-",month,"-",year)
else:
if month==12:
print(1,"-",1,"-",year+1)
else:
print(1,"-",month+1,"-",year)
Inputs and outputs with various test cases :
Input 1: (General test)
Enter the day :1
Enter the month :9
Enter the year :2015
Output 1:
2 - 9 - 2015
Input 2: (Last date of an year)
Enter the day :31
Enter the month :12
Enter the year :2000
Output 2:
1 - 1 - 2001
Input 3: (Leap year, february checking)
Enter the day :28
Enter the month :2
Enter the year :2000
Output 3:
29 - 2 - 2000
Input 4: (Not a leap year, Century year, february checking)
Enter the day :28
Enter the month :2
Enter the year :1900
Output 4:
1 - 3 - 1900
Explanation :
First, we need to find out whether the given year is leap year or not. If yes, we need to make the no.of days on february to 29; else 28. Similarly, on listing the 30 day months(4), we need to update their month lengths to 30 (because they are less in numer, so, it decreases time complexity, compared to 31 day months (7)), and all other months length should be filled with 31.
On finding year type and month, we need to go with date. If date is less than the specified month, just incrementing te date by 1 makes the work done. else, the date will be equal to month length. Then we need to make day as 1, incrementing the month, leaving year the same. If the month is 12 and date is 31, update the date and month to 1, and increment year by 1. That's it.
Note : I have added the attachments of the interpretation and the execution of programs with their outputs. Take a look!
Quick Tip : In python, you must and should follow Indentation. Following the indentation property in any programming language will help you in quickly analysing the code, if an error occurs.
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