Question

Write a python program to sum the series 1²/1 + 2^2/2 + 3^2/3 +...+n^2/n.​

Answer 1

Answer:

Sum = (Number * (Number + 1) * (2 * Number + 1 )) / 6

Sum = (6 * (6 + 1) * (2 * 6 +1)) / 6 => (6 * 7 * 13) / 6

and the output, Sum = 91

Explanation:

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