Question

write a python program to take n numbers as input and count the even numbers and print the output .​

Answer 1

Answer:

a=int(input("Enter number of numbers"))

count=0

for i in range(a):

n=int(input("Enter the number"))

if n%2==0:

count+=1

print(count)

Answer 2

★$\bf{\underline{Answer::}}$

n = int(input("Enter the number of elements to be inserted: "))

temp = 0

num = []

for i in range(n):

   num.append(int(input("Enter element {}: ".format(i+1))))

for nums in num:

   if nums % 2 == 0:

       temp += 1

print("Total even numbers: {}".format(temp))

★$\bf{\underline{Explanation::}}$

• In this program, we first take an integer input n from the user, which represents the number of elements to be inserted. We then create an empty list num to store the input numbers.
• Next, we use a for loop to take n numbers as input from the user and append them to the num list.
• After that, we use another for loop to iterate through the num list and check if each element is even or not using the modulo operator (%). If an element is even, we increment the count variable.
• Finally, we print the total number of even numbers by formatting the count variable using the print() function.