Question

write a python triplet whose one member is 12​

Answer 1

Answer:

12,35,37

Step-by-step explanation:

m=6

1st number = 2m= 2×6=12

2nd number = m^2-1= 6^2-1= 36-1= 35

3rd number = m^2+1= 6^2+1= 36+1= 37