Question

Write a quadractic equation whose sum is 5/6 and product is1/6

Answer 1

Correct Question: Write a quadractic equation whose sum of zeroes is 5/6 and product of zeroes is 1/6.

Answer:

$\large\boxed{\sf{6{x}^{2} - 5x + 1 = 0 }}$

Step-by-step explanation:

Let the zeroes of quadratic equation be alpha and beta .

According to question,

$\alpha + \beta = \frac{5}{6} \: \: \: and \: \: \: \alpha \beta = \frac{1}{6}$

We know that, quadratic equation is given by,

${x}^{2} - ( \alpha + \beta )x + \alpha \beta = 0$

Therefore, substitute the values,

$= > {x}^{2} - \frac{5}{6} x + \frac{1}{6} = 0 \\ \\ = > 6{x}^{2} - 5x + 1 = 0$

Answer 2

Answer:

6x² - 5x - 1

Step-by-step explanation:

Quadratic Equation of the form ax² + bx + c

Sum of zeroes = -b/a = 5/6

Product of zeroes = c/a = 1/6

a= 6 , b= -5 , c= 1

Equation = 6x² - 5x + 1