Write a quadratic equation whose roots are root3+1 and root3-1
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ANSWER:
We know that
Quadratic equation = x² - (sum of roots)x + product of roots
Given
- α = √3 + 1 , β = √3 - 1
Sum of roots (α + β) = √3 + 1 + √3 -1 = 2√3
Product of roots (αβ) = (√3 + 1)(√3 - 1)
Using
(a + b)(a - b) = a² - b²
Product of roots = (√3)² - (1)² = 3 - 1 = 2
Required quadratic equation = x² - 2√3x + 2
Hence , required quadratic equation is x² - 2√3x + 2 = 0
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