write a quadratic equation with roots 3 and 4
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Answer:
Quadratic Equation:
- alpha =3
- beta=4
sum of the zeroes=∝+β=3+4=7
product of zeroes=∝β=3×4=12
- k[x²-(∝+β)x+∝β]=0
- k[x²-7x+12]=0
- x²-7x+12=0
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