Question

write a quadratic polynomial having zeroes 1&-2.​

Answer 1

Answer:

The two zeros are 1 and -2

so,

the quadratic equation is given by

k{X²-(sum of zeros)X+(Produc of zeros)}

P(X) = K{X²-(1+(-2))X+(1×(-2))}

P(X) = k{ X²+X-2}

Let, P(X) = 0

•°• P(X) = X² + X - 2

Answer 2

Answer:

Zeroes = 1, (-2)

Sum = (-1)

Product = (-2)

Polynomial = x^2 -(sum) + product

Polynomial = x^2 + x - 2