Question

write a quadratic polynomial sum of who zeroes are 2 and product is - 8​

Answer 1

$\huge\mathbb\red{ANSWER}$

Given

sum of zeros = 2

product of zeros = -8

$as \: we \: know \: sum \: of \: zeros \: = \alpha + \beta \\ \\ so \: \alpha + \beta = 2 \\ \\ also \: product \: of \: zeros \: = \alpha \beta \\ \\ then \: \alpha \beta = - 8 \\ \\ by \: using \: formula \\ \\ \large\color{brown}{{x}^{2} -(\alpha+\beta)x+ \alpha \beta } \\ \\ by \: puting \: value \: in \: formula \: \\ \\ {x}^{2} - 2x \: + ( - 8) \\ \\ {x}^{2} - 2x \: - 8 \: is \: \: required \: polynomial$

$\huge\mathbb\green{EXPALNATION}$

• 1st we find product and sum of zeros

• then we apply formula

• this formula is only applicable for a quadratic equations

hope it helps you

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