Question

write a quadratic polynomial , sum of whose zeroes is 2√3 and product is 5​

Answer 1

Answer:

The polynomial is : X^2 - 2√3 X + 5

Step-by-step explanation:

from the equation => X^2 - (Sum of zeros)X + (Product of zeros)

Given:

Sum of zeros = 2√3

Product of zeros = 5

So the polynomial is => X^2 - 2√3 X + 5

Answer 2

Answer:

p(x)= x²-2root3x+5

Step-by-step explanation:

$p(x) = k{x}^{2} - ( \alpha + \beta )kx + \alpha \beta k$

After applying the Values,

$\alpha + \beta = 2 \sqrt{3}$

$\alpha \beta = 5$

Take out 'k' common

Thus

p(x)=x²-2root3x+5