Write a quadratic polynomial, sum of whose zeroes is 2 and product is -8.
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Answered by
0
Answer:
Step-by-step explanation:
sum of zeroes = 2
product of zeroes = -8
k [x² - ( sum of zeroes )x - product of zeroes]
k [ x² - 2x + 8]
Answered by
1
Answer:
k ( x^2 - 2x - 8)
Step-by-step explanation:
sum of zeroes=2
product=-8
formula for quadratic polynomial = k ( x^2 - (sum of zeroes)x + (product of zeroes))
k ( x^2-2x+(-8))
k ( x^2 - 2x - 8)
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