Write a quadratic polynomial, sum of whose zeroes is 3root3 and their product is 6.
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Answers
Answered by
6
Heya !!!
Sum of zeroes = Alpha + Beta = 3✓3
And,
Product of zeroes = Alpha × Beta = 6
Therefore,
Required Quadratic polynomial = X²-(Sum of zeroes)X + Product of zeroes
=> X²-(3✓3)X + 6
=> X²-3✓3X+6.
HOPE IT WILL HELP YOU....... ;-)
Sum of zeroes = Alpha + Beta = 3✓3
And,
Product of zeroes = Alpha × Beta = 6
Therefore,
Required Quadratic polynomial = X²-(Sum of zeroes)X + Product of zeroes
=> X²-(3✓3)X + 6
=> X²-3✓3X+6.
HOPE IT WILL HELP YOU....... ;-)
Answered by
6
Heya !!!
Here is your answer.
Given :
Sum of zeroes = 3√3
Product of Zeroes = 6.
Using the quadratic equation...
p(x) = kx² - (sum of zeroes)x + (product of zeroes)
p(x) = x² - 3√3x + 6
Hope It Helps
Here is your answer.
Given :
Sum of zeroes = 3√3
Product of Zeroes = 6.
Using the quadratic equation...
p(x) = kx² - (sum of zeroes)x + (product of zeroes)
p(x) = x² - 3√3x + 6
Hope It Helps
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