Question

Write a quadratic polynomial, sum of whose zeroes is 4 and product is -8.​

Answer 1

Answer:

$x^{2}-4x-8=0$

Step-by-step explanation:

$\alpha + \beta =4\\\alpha \beta =-8$

Now, equation with product and sum given is:

$x^{2}-(sum \ of \ roots)x+(product \ of \ roots) = 0\\x^{2} - (4)x+(-8)=0\\x^{2}-4x-8=0$