Question

write a quadratic polynomial the sum of whose zero is -3 and products -10
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Answer 1

Step-by-step explanation:

Given:-

the sum of whose zero is -3 and products -10

To find:-

write a quadratic polynomial the sum of whose zero is -3 and products -10

Solution:-

Sum of the zeroes = -3

Product of the zeroes = -10

We know that

If α and β are the zeroes of the given pilynomial then the quadratic pilynomial is

K [x^2-(α +β )x+αβ ]

Where K is a constant.

Now we have

α + β = -3

α β = -10

On Substituting the values in the above formula

=> K [x^2-(-3)x+(-10)]

=>K[x^2+3x-10]

If K = 1 then the required pilynomial is x^2+3x-10

Answer:-

The required quadratic polynomial is x^2+3x-10

Used formula:-

If α and β are the zeroes of the given pilynomial then the quadratic pilynomial is

K [x^2-(α +β )x+αβ ]

Where K is the constant.

Additional information:-

• The general form of a quadratic polynomial is ax^2+bx+c

• It has at most two zeores because its degree is 2

• The graph of the quadratic polynomial is a parabola