Write a quadratic polynomial the sum of whose zeroes is -3 and product is -10.
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Answer: 2x²+26+60
Step-by-step explanation: General form of a quadratic polynomial is kx²- k(α-β)x + kαβ or k[x²- (α+β)x + ab].
So, by the given condition, the polynomial will be k[x²- (-3-10)+ (-3×-10)].
=k[x²-(-13)+ 30]
=k(x²+13+30) (here, k is a variable which can take any value)
=2(x²+13+30) (let k=2)
=2x²+26+60
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