Write a quadratic polynomial whose one zero is 3-√5 and Product of zeros is 4.
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Solution :-
Given,
- one zero of the quadratic polynomial = 3 - √5
- Product of roots or zeroes = 4
✤ Firstly finding other root of the quadratic polynomial .
Let the other root be x
➜ x ( 3 - √5 ) = 4
➜ x = 4/ (3 - √5)
➜ x = 4 ( 3 + √5 )/ ( 3 - √5 ) ( 3 + √5 )
➜ x = 12 + 4√5 / 3² - (√5)²
➜ x = 4(3 + √5) / 9 - 5
➜ x = 4(3 + √5)/4
➜ x = 3 + √5 = Other root of the quadratic polynomial
✤ Now finding the quadratic polynomial .
♦ Quadratic polynomial = x² - (sum of roots)x - product of roots
☞ x² - ( 3 + √5 + 3 - √5 ) x + [ ( 3 + √5 )( 3 - √5 ) ]x
☞ x² - 6x + [ 3² - ( √5 )² ]
☞ x² - 6x + [ 9 - 5 ]
☞ Quadratic polynomial = x² - 6x + 4
Hence,quadratic polynomial is x² - 6x - 4
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Use this formula
x = -b ±√b² - 4ac/2a
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