write a quadratic polynomial whose one zero is 3-root5 and product of zeroes is 4
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4/3-√5=4*3+√5/(3-√5)(3+√5)
4(3+√5)/(3)^2-(√5)^2
4(3+√5)/9-5
4(3+√5)/4
3+√5
sum of zeroes=(3-√5)+(3+√5)
=3+3
=6
f(X)=X^2-(sum of zeroes)X+product of zeroes
=x^2-6x+3√5
4(3+√5)/(3)^2-(√5)^2
4(3+√5)/9-5
4(3+√5)/4
3+√5
sum of zeroes=(3-√5)+(3+√5)
=3+3
=6
f(X)=X^2-(sum of zeroes)X+product of zeroes
=x^2-6x+3√5
Muzammil10225:
bekar hai
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